10=k(2+3)^2

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Solution for 10=k(2+3)^2 equation: 



10=k(2+3)^2

We move all terms to the left:

10-(k(2+3)^2)=0

We add all the numbers together, and all the variables

-(k5^2)+10=0

We add all the numbers together, and all the variables

-k5^2+10=0

We move all terms containing k to the left, all other terms to the right

-k5^2=-10

k=-10/1

k=-10

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